Thursday 30 March 2017


Q1 .A sample of 0.025 mol of the chloride of an element Z was dissolved in distilled water and the solution made up to 500cm3. 12.5cm3 of this solution reacted with 25cm3 of 0.1 moldm-3 silver nitrate solution. What is the formula of the chloride?


A. Z2Cl    B. ZCL   C. ZCl2   D. ZCl4


Help:

Silver (I) Chloride reacts with Chloride to give silver (I) chloride percipitate : 

                                Ag+ (aq)    +   Cl- (aq) -------------> AgCl (s)

The amount of Aq+ used? = Concentration X volume

                                                       = o.1 (mol dm^-3)  x  (25/1000) (dm^3)
                                                      = 2.5 x 10^-3

Since 1 mole of Ag+ react with 1 mole of Cl- ,  Amount of Cl- present in 12.5 cm^3     =2.5x10^-3/12.5 x 500
                                                                                                                                                                             = 0.1 mol


Since 0.025 mole of compound contain o.1 mole of chloride, I mole of the compound therefore contain
0.1/0.025 = 4 mole of chloride. 

The Formula for the compound is ZCl4

Answer is D

Q2)  In the absence of a catalyst, ammonia burns in an excess of Oxygen to produce steam and nitrogen. What is the volume of oxygen, remaining when 60 cm^3 of ammonia is burnt in 100 cm^3 of oxygen, all  the volume being measured at the same temperature and pressure?

A 25 cm^3   B 35cm^3  C 40 cm^3  D 45 cm^3  E 55cm^3



Help

4 NH3 (g)  +  3O2 (g)  ----------> 2N2 (g) + 6 H2O (g)


60 cm^3 of NH3  requires 3/4 X 60 = 45cm^3 of O2

Therefore, Volume of Excess O2= 100-45=55 cm^3



Q4 A sample of 10dm^3 of populated air is passed through the lime water so that all of the carbon dioxide present is precipitated as calcium carbonate. The mass of calcium carbonate formed is  0.05 g. What is the percentage, By volume of  carbon dioxide in the air sample?

{Relative Atomic Masses C, 12 O 16; Ca 40; I mole of gas under the experimental conditions has a voulme of 24 dm^3}


A 0.03%  B  0.05  %   C 0.12%  D 0.3 %


Help

Ca(OH)2 (aq)  +  CO2(g)-----------> CaCO3 (s) + H2O

Amount of precipitated = 0.05/40+12+3 x 6
                                                 =  5.0 X 10^-4 x 24
                               
Therefore the volume of CO2= 5.0  x 10^-4 x 24
                                                = 1.2x10^-2  dm^3

Therefore, % volume of CO2 =1.2 x 10^-2 /  10    X 100
                                                = 0.12

Answer C


Q5

A sample of 2.00 g of iron (III) sulphate, Fe2(SO4)3, is dissolved in water to give 100 cm^3 of aquous solution. What is the concentration of SO4^2- ions? { The relative formula (molecular) mass of Fe2(SO4)3 IS 400} 


A 1.5 x 10^-3 mol dm^-3
B   5  x 10^-3 mol dm^-3
C 1.5 x 10^-2 mol dm^-3
D 5    x 10^-2 mol dm^-3
E 1.5 x 10^-1 mol dm^-3


Help

1 mole of Fe2 (So4)3 gives 3 mole of SO4^2-  ions.
Therefore, Concentration of SO4^2- = (2.00/400  /   100/1000)   X  3
                                                           = 0.15 mol dm^-3


Q6

What is the volume of Oxygen is required for the complete combustion of mixture of 5 cm^3 of CH4 and 5 cm^3 of C2H4?

A 5cm^3   B 10 cm^3  C  15 cm^3  D 20 cm^3 E 25 cm^3

Help

CH4 (g) + 2O2 (g)--------> CO2(g) + 2H2O (l)
C2H4 (g) + 3O2(g)------->2CO2 (g) + 2H20 (l)

Volume of O2 required to burn 5 cm^3 of CH
= 2x5=10cm^3
Volume of O2 required to burn 5 cm^3 of C2H4
= 3 x 5 =15 cm3
Total Volume of O2 required
= 10+15=25cm^3

Answer E



Q7 In which of the following reactions does hydrogen behave as an oxidizing agent?

A H2 + Cl2---------> 2HCl
B C2H4 + H2------->C2H6
C C2H5CHO + H2------->C2H5CH2OH
D N2 + 3H2-------->2NH3
E 2Na + 3H2-------->2NaH



Help
An Oxidising






































Topical Mcq Chemistry A level- Atoms, Molecules and Stoichiometry

Q1 .A sample of 0.025 mol of the chloride of an element Z was dissolved in distilled water and the solution made up to 500cm3. 12.5cm3 of this solution reacted with 25cm3 of 0.1 moldm-3 silver nitrate solution. What is the formula of the chloride?

A. Z2Cl    B. ZCL   C. ZCl2   D. ZCl4


Help:

Silver (I) Chloride reacts with Chloride to give silver (I) chloride percipitate : 

                                Ag+ (aq)    +   Cl- (aq) -------------> AgCl (s)

The amount of Aq+ used? = Concentration X volume

                                                       = o.1 (mol dm^-3)  x  (25/1000) (dm^3)
                                                      = 2.5 x 10^-3

Since 1 mole of Ag+ react with 1 mole of Cl- ,  Amount of Cl- present in 12.5 cm^3     =2.5x10^-3/12.5 x 500
                                                                                                                                                                             = 0.1 mol


Since 0.025 mole of compound contain o.1 mole of chloride, I mole of the compound therefore contain
0.1/0.025 = 4 mole of chloride. 

The Formula for the compound is ZCl4

Answer is D







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9701/01 Paper 1 Multiple Choice May/June 2008

Q1 For each question there are four possible answers, A, B, C, and D. Choose the one you consider to be correct.

1 In the Basic Oxygen steel-making process the P4O10 impurity is removed by reacting it with calcium oxide. The only product of this reaction is the salt calcium phosphate, Ca3(PO4)2. In this reaction, how many moles of calcium oxide react with one mole of P4O10?

A 1          B 1.5          C 3         D 6 

Solution


A level Chemistry Practical

1,I have a trouble in making deductions ,for cation and anion tests!
2,I also have trouble in making observations for gases,because i fail to understand for which reaction should i place the litmus papers on the test tube. :? 


Place the litmus paper whenever you see the mixture in the test tube bubbling.

The Qualitative analysis is given at the back. First fall arrange your test tube in an order which you can work with quickly, don't just put them randomly to mix them up! Secondly, take small amounts of liquids in the test-tubes to get faster results. You only need an approximate volume to the one given in the qst. See the qualitative analysis for the reagent that you are using. For example you are using sodium hydroxide (aq) then see the column of sodium hydroxide(aq) and try to match the colour changed that happened, if any. Thats all that you need to do. Apart from this only practice will help.

then you should keep calm
dont just jump onto conslusions
slowly and carefully
take care not to be too slow too!!!
and as u go on writing  your observations , write somewhere next to it the ions u would go for i mean white precipitate for Al , Zn and Ca when NaOH is added
i think i am right
anyways
u gotta write it and then strike out as u proceed in the end ur left with the answer!

A level Biology Practical notes!!


GRAPHS!
1.the value which is varying is always on the y-axis while the constant value is on the x-axis.
2.no unbroken lines
3.it must be neat and thin
4.the points can be joined using a ruler or by hand
5.do not draw beyond the plotted points.
6.blobs or centre points more than 1mm are NOT acceptable
7.if zero is present in the reading, ur graph MUST pass through zero.
8.label both axis!
9.use appropriate units
10.use appropriate scale
11.use sharpened pencil to plot
12.plot the dots within circles, of equal sizes, must be clear and not too big.

SOURCES OF ERRORS!
1.temp nt controlled
2.pH not controlled or nt measured accurately
3.difficulty in judging the colour.
4.difficulty in having the same time
5.inaccuracy in preparing serial dilution
6.inaccuracy of equipment, fr e.g. pipette/syringe
7.too short time.
8.evaporation of the solution which can cause the concentration to change.

LIMITATIONS OF ERRORS!
1.measure the volume accurately using syringe with narrow range of calibration
2.repeat more times at each pH/conc./temp
3.use range of pH/conc./temp
4.accurate specific measuring devices
5.use colorimeter to measure the degree of colourness.
6.use buffer to control pHs
7.use of water bath/thermostat to control temp
8.use thermometer to measure the temp.
9.thermostatically controlled environment.
10.repeat with each conc.
11.volume of the sample(e.g. enzyme/substrate) must be the same..cuz as volume increases, conc also increases
12.keep only one factor different, and all others must be the same.

Reliability.....take minimum of 3 readings!
repeat with mre pH/conc/temp
and find out their mean
Accuracy.....seing electronic thermostat
use of pippettes instead of measuring cylinders

KEY
1)read the whole question till the end
2)decide number of readings to take
3)don't go for more or less than 3 readings per conc/vol of any ques.
4)make a table
5)write down the UNITS in each coloumn of the table...e.g. conc/cm^3 , temp/°C

MICROSCOPY!!!

1)propotion of thickness must be correct.
2)draw the organelles where u see them, dont just draw anywhere within the cell! never draw what u know.
3)whenever u see the plant cells, draw the cell walls.
4)IN PLAN DIAGRAMS, NO DRAWING OF ANY CELLS, AND NO SHADING...if u'll do either of them, u'll lose the whole mark!!
5)when asked to draw 2 cells, draw the ones that are easiest to draw. and dont draw more then 2 cells!
6)fraw the adjacent (touching) cells.
7)drawing should be large, unshaded.
8)in plan diagrams show the relative thickness of each layer.
9)draw the exact shape, if its oval or round or has wavy outlines
10)label the diagram...simplest thing to label is cytopasm, nucleus and cell membrane.
11)if its a trachea cell, then label goblet cells, cilia, blood vessels, muscular tissue, cartilage cells (lacunae)
12) when asked to compare 2 diagrams....make a table (drawing a table itself has 1 mark!)....put atleast one similarity

ERRORS IN MESUREMENTS!

1)irregular in shape
2)difficulty in focusing
3)preperation is squashed

and yeahhhh one more thingg, the values must be whole numbers!!! e.g if its 8.5mm u round it off to a whole number which is 9!!

Simple dilution and Serial dilution??

Serial dilution is actually very easy. If you have 30cm3 of 10% enzyme solution (example) you take 20cm3 of that 10% in put it in beaker 1. From this 20cm3 in beaker 1, take another 10cm3 and place it in beaker 2 and add 10cm3 of water. This dilutes the solution into 5%. Do the same thing for beaker 3, take 10cm3 of the 5% solution and add 10cm3 of water in beaker 3 to get 2.5% solution.
This way you have:
Beaker 1 - 10% enzyme solution
Beaker 2 - 5% enzyme solution
Beaker 3 - 2.5% enzyme solution




Usually you get a specimen on a slide or a photomicrograph to draw a plan diagram. 

For a low power drawing 

1. you must not draw individual cells when drawing a plane diagram.

2. draw only the outline of tissues.(don’t shade, draw thinner continuous lines.)

3. When drawing a specimen on a slide you can use high power to clearly see where the edges of

tissues.

4. Your drawing should cover more than the half of the space given.


When labelling(if you are asked to do so….)

1. label using a pencill and make sure the end of the line exactly touches the structure.

2. write the labels horizontally and outside the drawing itself.

3. Don't cross over the lines when labelling.










































A. Cell Structure (1)


 [PA] use an eyepiece graticule and stage micrometer scale to measure cells and be familiar with units (millimeter, micrometer, nanometer) used in cell studies; Calibration with a standard stage micrometer with pitch [0.1 mm]





(2) [PA] compare and contrast the structure of typical animal and plant cells;













































Characteristics and roles;

Root and Stem:
 ▪ Epidermis: surface of the stem made of a number of layers often with a waxy cuticle to reduce water loss.
Cortex Tissue:
 Forming a cylinder of tissue around the outer edge of the stem. Often contains cells with secondary thickening in the cell walls which provides additional support.
Vascular bundle:
 contains xylem, phloem and cambium tissue. ▪ Xylem: a longitudinal set of tubes that conduct water and mineral salts from the roots upward
Spongy mesophyll: 
contains spaces that allows the movement of gases and water through the leaf tissue..
Lower epidermis: 
bottom surface layer of tissues which contains the guard cells that form each stoma

(4) [PA] calculate linear magnification of drawings and photographs; m = (I/O) [I measured with a 30 cm rule and O with a calibrated eyepiece graticule] 
(5) [PA] calculate the actual sizes of specimens from drawings and photographs








Wednesday 29 March 2017

Cell Structure

b) calculate the linear magnifications of drawings, photomicrographs and electron micrographs

Genetics Doubts

explain y Io(gene for blood group o) is recessive to both iA and iB(ie alleles for blood group A and B respectively)..
2.Describe how a single base deletion in the allele Io leads to the synthesis of an inactive protein?


 O is always the recessive. It would barely shows unless it is recessive. As for a single base deletion, point mutation I'll call it. Base deletion will produce frame shift in a code. It might delete the gene coding for the shape of the active site or so, altering the tertiary structure of the protein. The substrate cannot bind to the active site and thus leading to an inactive protein. You look under cystic fibrosis. It's mostly cause by base deletion.

A level Biology Nervous System Doubts

 refractory period

Following the passage of one Action Potential, there is a time delay before the next one can pass. This time delay is known as refractory period and it lasts for a few milliseconds. During this time, the sodium channels in the membrane are closed, preventing the inward movement of Sodium ions. This is known as the absolute refractory period. Another impulse cannot be conducted no matter how large the stimulus is.

or


When an action potential has just occurred at a section of the axon, there is a short period of time when a second action potential can be generated at the same point. This is called the refractory period.

A level Biology-Photosynthesis Doubts

Can somebody tell me how do I write the answer to this question:

Explain the role of NADP in photosynthesis. [6]

Mark Scheme points are as follows:

15 coenzyme ;
16 reduced ;
17 carries protons ;
18 and (high energy) electrons ;
19 from photosystem7light stage ; R photosystem II
20 on thylakoid membrane grans ;
21 to stroma / Calvin cycl~
22 ref. regeneration of NADP ;




 You just need to elaborate these points.
The co-enzyme NADP is used to add hydrogen in CO2 to produces carbohydrate molecule such as glucose. in the light dependent stage,after the photophosphorylation, and at the end of the electron carrier chain, the electron is picked up by PS1 to replace the electron the chlorophyll in PSI had lost in the initial stages. Now these electrons are again passed from PSI to a different chain of carriers to NADP. The NADP also picks up the hydrogen ions from the split water molecules. The NADP becomes reduced now which will be used further in the light independent stage to convert the glycerate 3 phosphate into triose phoshphate which is the 1st carbohydrate to be produced in the photosynthesis.


or


NADP is a co-enzyme that serves as an electron acceptor in the electron transport system during photophosphorylation. The electrons released from the 'excited' chlorophyll in PS1 combine with an electron acceptor and pass down a chain that ends with NADP. During photolysis of water, the protons from the splitting of the water molecule help to form reduced NADP along with the electrons from PS1 that combined with the NADP. The reduced NADP then passes along the electrons on to the calvin cycle. During this cycle, glycerate phosphate is reduced to another 3C sugar called triose phosphate, which is phosphoglyceraldehyde by using the reduced NADP from the light dependent stage as the electron donor and ATP is required. NADP then returns to the light dependent stage to pick up another hydrogen ion. 

9702/01 Paper 1 Multiple Choice

1 Which of the following is a scalar quantity?  A acceleration    B mass      C momentum     D velocity Answer 1- B because mass has m...